A super-ball is to bounce elastically back and forth between two rigid walls at a distance d from each other. Neglecting gravity and assuming the velocity of super-ball to be v 0 horizontally, the average force (in large time interval) being exerted by the super-ball on one wall is :
Text Solution
Verified by ExpertsThe correct answer is:
B
t =
(time for succeesive collision)
N × t = dP = mv 0 – (–mv 0 )
N ×
= 2mv 0 ∴ N = 

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